Oracle Complicated Query
· To fetch
ALTERNATE records from a table. (EVEN NUMBERED)
select * from emp where rowid in (select decode(mod(rownum,2),0,rowid, null) from emp);
select * from emp where rowid in (select decode(mod(rownum,2),0,rowid, null) from emp);
· To select
ALTERNATE records from a table. (ODD NUMBERED)
select * from emp where rowid in (select decode(mod(rownum,2),0,null ,rowid) from emp);
select * from emp where rowid in (select decode(mod(rownum,2),0,null ,rowid) from emp);
· Find the
3rd MAX salary in the emp table.
select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2 where e1.sal <= e2.sal);
select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2 where e1.sal <= e2.sal);
· Find the 3rd
MIN salary in the emp table.
select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2where e1.sal >= e2.sal);
select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2where e1.sal >= e2.sal);
· Select
FIRST n records from a table.
select * from emp where rownum <= &n;
select * from emp where rownum <= &n;
· Select LAST
n records from a table
select * from emp minus select * from emp where rownum <= (select count(*) - &n from emp);
select * from emp minus select * from emp where rownum <= (select count(*) - &n from emp);
· List dept
no., Dept name for all the departments in which there are no employees in the
department.
select * from dept where deptno not in (select deptno from emp);
alternate solution: select * from dept a where not exists (select * from emp b where a.deptno = b.deptno);
altertnate solution: select empno,ename,b.deptno,dname from emp a, dept b where a.deptno(+) = b.deptno and empno is null;
select * from dept where deptno not in (select deptno from emp);
alternate solution: select * from dept a where not exists (select * from emp b where a.deptno = b.deptno);
altertnate solution: select empno,ename,b.deptno,dname from emp a, dept b where a.deptno(+) = b.deptno and empno is null;
· How to get
3 Max salaries ?
select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal <= b.sal) order by a.sal desc;
select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal <= b.sal) order by a.sal desc;
· How to get
3 Min salaries ?
select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal >= b.sal);
select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal >= b.sal);
· How to get
nth max salaries ?
select distinct hiredate from emp a where &n = (select count(distinct sal) from emp b where a.sal >= b.sal);
select distinct hiredate from emp a where &n = (select count(distinct sal) from emp b where a.sal >= b.sal);
· Select
DISTINCT RECORDS from emp table.
select * from emp a where rowid = (select max(rowid) from emp b where a.empno=b.empno);
select * from emp a where rowid = (select max(rowid) from emp b where a.empno=b.empno);
· How to
delete duplicate rows in a table?
delete from emp a where rowid != (select max(rowid) from emp b where a.empno=b.empno);
delete from emp a where rowid != (select max(rowid) from emp b where a.empno=b.empno);
· Count of
number of employees in department wise.
select count(EMPNO), b.deptno, dname from emp a, dept b where a.deptno(+)=b.deptno group by b.deptno,dname;
select count(EMPNO), b.deptno, dname from emp a, dept b where a.deptno(+)=b.deptno group by b.deptno,dname;
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